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JEE Main 202315 AprilMorning Shift
Exam
JEE Main
Year
2023
Date
15 April
Shift
Morning Shift
Subject
Physics
Chapter
Electromagnetic Induction

JEE Main 2023 · 15 April · Morning Shift · Physics · Electromagnetic Induction

A 20cm long metallic rod is rotated with 210rpm about an axis...

A 20cm20cm long metallic rod is rotated with 210rpm210rpm about an axis normal to the rod passing through its one end. The other end of the rod is in contact with a circular metallic ring. A constant and uniform magnetic field 0.2T0 . 2T parallel to the axis exists everywhere. The emf developed between the centre and the ring is _________mVmV.

(Take π=227\pi = \dfrac{22}{7})

Correct answer

0

Step-by-step solution

The data given is

ω=210×2π60rads−1=7πrads−1l=0.2mB=0.2T\omega = 210 \times \dfrac{2\pi}{60}rad{s}^{- 1} = 7\pi rad{s}^{- 1}l = 0 . 2mB = 0 . 2T

The emf is given by

ε=Bωl22ε = \dfrac{B\omega{l}^{2}}{2}

=0.2×7π×(0.2)22= 0 . 2 \times 7\pi \times \dfrac{{\left(0 . 2\right)}^{2}}{2}

=88mV= 88mV

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