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JEE Main201910 Jan 2019Morning ShiftPhysicsElectromagnetic InductionActual

A solid metal cube of edge length 2 cm is moving in the positive y -direction, at a constant speed of 6 m s - 1 . There is a uniform magnetic field of 0.1 T in the positive z -direction. The potential difference between the two faces of the cube, perpendicular to the x -axis, is

Options

  1. A12   mV
  2. B1   mV
  3. C2   mV
  4. D6   mV

Correct answer

A. 12   mV

Step-by-step solution

emf developed is given by, e = Bvl ∴ e = 0.1 2 × 10 - 2 × 6 ⇒ e = 12 × 10 - 3 = 12   mV

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