A uniform electric field of 10 N C - 1 is created between two parallel charged plates (as shown in figure). An electron enters the field symmetrically between the plates with a kinetic energy 0 . 5 eV . The length of each plate is 10 cm . The angle ( θ ) of deviation of the path of electron as it comes out of the field is ______(in degree).

Step-by-step solution

Given here, kinetic energy 1 2 e = 1 2 m u x 2 ⇒ u x = e m Acceleration of electron due to electric field is a = e E m , where, e is charge on electron. Using equation of motion, s = u x t + 1 2 a x t 2 along x direction, we get L = u x t + 0 ∵ a x = 0 ⇒ 10 × 10 - 2 = u x t ⇒ t = 10 - 1 u x         . . . . 1 Using equation of motion, v y = u y + a y t along y direction, we get v y = 0 + e E m t = e E m t       . . . 2 From equation 1   and