JEE Main 20248 AprilMorning Shift
- Exam
- JEE Main
- Year
- 2024
- Date
- 8 April
- Shift
- Morning Shift
- Subject
- Physics
- Chapter
- Experimental Physics
JEE Main 2024 · 8 April · Morning Shift · Physics · Experimental Physics
The diameter of a sphere is measured using a vernier caliper whose...
The diameter of a sphere is measured using a vernier caliper whose 9 divisions of main scale are equal to 10 divisions of vernier scale. The shortest division on the main scale is equal to . The main scale reading is and second division of vernier scale coincides with a division on main scale. If mass of the sphere is 8.635 g, the density of the sphere is:
Options
- A
- B
- C
- D
Correct answer
A.
Step-by-step solution
Given Reading of diameter $=\mathrm{MSR}+\mathrm{LC} \times \mathrm{VSR}\begin{aligned} & =2 \mathrm{~cm}+(0.01) \times(2) \\ & =2.02 \mathrm{~cm}\end{aligned}$$=\frac{4}{3} \pi\left(\frac{d}{2}\right)^3=\frac{4}{3} \pi\left(\frac{2.02}{2}\right)^3 =4.32 \mathrm{~cm}^3=\frac{\text{ mass }}{\text{ volume }}=\frac{8.635}{4.32}=1.998 \sim 2.00 \mathrm{~g}$