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The diameter of a sphere is measured using a vernier caliper whose 9 divisions of main scale are equal to 10 divisions of vernier scale. The shortest division on the main scale is equal to 1 ~mm . The main scale reading is 2 ~cm and second division of vernier scale coincides with a division on main scale. If mass of the sphere is 8.635 g, the density of the sphere is:

Options

  1. A2.0 ~g / cm ^3
  2. B1.7 ~g / cm ^3
  3. C2.2 ~g / cm ^3
  4. D2.5 ~g / cm ^3

Correct answer

A. 2.0 ~g / cm ^3

Step-by-step solution

Given 9 MSD =10 VSD mass =8.635 ~g aligned & LC =1 MSD -1 VSD & LC =1 MSD - 9 10 MSD & LC = 1 10 MSD & LC =0.01 ~cm aligned Reading of diameter = MSR + LC VSR aligned & =2 ~cm +(0.01) (2) & =2.02 ~cm aligned Volume of sphere = 4 3 ( d 2 )^3= 4 3 ( 2.02 2 )^3=4.32 ~cm ^3 Density = mass volume = 8.635 4.32 =1.998 2.00 ~g

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