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JEE Main 202310 AprilEvening Shift
Exam
JEE Main
Year
2023
Date
10 April
Shift
Evening Shift
Subject
Physics
Chapter
Experimental Physics

JEE Main 2023 · 10 April · Evening Shift · Physics · Experimental Physics

In an experiment with vernier callipers of least count 0 . 1mm ,...

In an experiment with vernier callipers of least count 0.1mm0 . 1mm, when two jaws are joined together the zero of vernier scale lies right to the zero of the main scale and 6th{6}^{th} division of vernier scale coincides with the main scale division. While measuring the diameter of a spherical bob, the zero of vernier scale lies in between 3.2cm3 . 2cm and 3.3cm3 . 3cm marks and 4th{4}^{th} division of vernier scale coincides with the main scale division. The diameter of bob is measured as

Options

  1. A3.22cm3 . 22cm
  2. B3.18cm3 . 18cm
  3. C3.26cm3 . 26cm
  4. D3.25cm3 . 25cm

Correct answer

B. 3.18cm3 . 18cm

Step-by-step solution

The least count is LC=0.1mmLC = 0 . 1mm

Zero error (ZE)=6×LC=6×0.1mm=0.6mm( ZE ) = 6 \times LC = 6 \times 0 . 1mm = 0 . 6mm

The total reading is TR=MSR+(VSR×LC)−ZE⇒TR=32mm+(0.1×4)mm−0.6mm⇒TR=31.8mm=3.18cmTR = MSR + \left(VSR \times LC\right) - ZE ⇒ TR = 32mm + ( 0 . 1 \times 4 ) mm - 0 . 6mm ⇒ TR = 31 . 8mm = 3 . 18cm

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