In a Vernier Caliper 10 divisions of Vernier scale is equal to the 9 divisions of main scale. When both jaws of Vernier calipers touch each other, the zero of the Vernier scale is shifted to the left of zero of the main scale and 4 th Vernier scale division exactly coincides with the main scale reading. One main scale division is equal to 1 mm . While measuring diameter of a spherical body, the body is held between t

Step-by-step solution

Given that 1   M . S . D = 1   mm And 9   M . S . D   = 10   V . S . D ⇒ 1   V . S . D = 0 . 9 M . S . D = 0 . 9   mm L.C of vernier caliper = 1 - 0 . 9 = 0 . 1   mm = 0 . 01   cm Zero error = 10 - 4 × 0 . 1   mm = 0 . 6   mm as at zero the, the zero of the vernier is shifted towards left zero error is negative. Therefore, zero error = - 0 . 6   mm . Reading = M . S . R + V . S . R - Zero error Reading = 3 + 6 × 0 . 01 - - 0 . 06 Reading =