JEE Main202125 Jul 2021Morning ShiftPhysicsExperimental PhysicsActual
Student A and student B used two screw gauges of equal pitch and 100 equal circular divisions to measure the radius of a given wire. The actual value of the radius of the wire is 0 . 322   cm . The absolute value of the difference between the final circular scale readings observed by the students A and B is _______. [Figure shows position of reference O when jaws of screw gauge are closed] Given pitch = 0 . 1 &#
Correct answer
0
Step-by-step solution
For A , Reading = M S R + C S R + Error 0 . 322 = 0 . 300 + C S R + 5 × L C 0 . 322 = 0 . 300 + C S R + 0 . 005 C S R = 0 . 017 For B , Reading = M S R + C S R + Error 0 . 322 = 0 . 200 + C S R + 0 . 092 C S R = 0 . 030 Difference = 0 . 030 - 0 . 017 = 0 . 013   cm Division on circular scale = 0 . 013 0 . 001 = 13