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JEE Main 202116 MarchMorning Shift
Exam
JEE Main
Year
2021
Date
16 March
Shift
Morning Shift
Subject
Physics
Chapter
Experimental Physics

JEE Main 2021 · 16 March · Morning Shift · Physics · Experimental Physics

One main scale division of a vernier callipers is a cm and n ^ th...

One main scale division of a vernier callipers is aa cmcm and nth{n}^{th} division of the vernier scale coincide with (n−1){\left(n - 1\right)}^{th}divisionofthemainscale.Theleastcountofthecallipersindivision of the main scale. The least count of the callipers inmm is :

Options

  1. A\dfrac{10na}{\left(n - 1\right)}
  2. B\dfrac{10a}{\left(n - 1\right)}
  3. C\dfrac{\left(n - 1\right)}{10n}
  4. D10an\dfrac{10a}{n}

Correct answer

D. 10an\dfrac{10a}{n}

Step-by-step solution

(n−1)a=n(a′)\left(n - 1\right)a = n\left({a}^{'}\right)

a′=(n−1)an{a}^{'} = \dfrac{\left(n - 1\right)a}{n}

∴L.C.=1MSD−1VSD∴ L . C . = 1MSD - 1VSD

=(a−a′)cm= \left(a - {a}^{'}\right)cm

=a−(n−1)an= a - \dfrac{\left(n - 1\right)a}{n}

=na−na+an=ancm= \dfrac{na - na + a}{n} = \dfrac{a}{n}cm

=(10an)mm= \left(\dfrac{10a}{n}\right)mm

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