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JEE Main 20206 SeptemberEvening Shift
Exam
JEE Main
Year
2020
Date
6 September
Shift
Evening Shift
Subject
Physics
Chapter
Experimental Physics

JEE Main 2020 · 6 September · Evening Shift · Physics · Experimental Physics

A student measuring the diameter of a pencil of circular...

A student measuring the diameter of a pencil of circular cross-section with the help of a vernier scale records the following four readings 5.50mm5 . 50mm, 5.55mm5 . 55mm, 5.34mm5 . 34mm, 5.65mm5 . 65mm. The average of these four reading is 5.5375mm5 . 5375mm and the standard deviation of the data is 0.07395mm0 . 07395mm. The average diameter of the pencil should therefore be recorded as :

Options

  1. A(5.5375±0.0739)mm\left(5 .5375 \pm 0 .0739\right)mm
  2. B(5.5375±0.0740)mm\left(5 .5375 \pm 0 .0740\right)mm
  3. C(5.538±0.074)mm\left(5 .538 \pm 0 .074\right)mm
  4. D(5.54±0.07)mm\left(5 .54 \pm 0 .07\right)mm

Correct answer

D. (5.54±0.07)mm\left(5 .54 \pm 0 .07\right)mm

Step-by-step solution

Significant rule says that reading should has same significant figure as that of reading given.

5.5375→5 . 5375 \to rounded to →5.54.</p><p>0.07395\to 5 . 54 .</p><p>0.07395\toroundedtorounded to\to0.07</p><p>therefore,<sub>(5.54±0.07)mm0.07</p><p>therefore, <sub>\left(5 . 54 \pm 0 . 07\right)mm

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