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JEE Main 20203 SeptemberMorning Shift

Exam: JEE Main
Year: 2020
Date: 3 September
Shift: Morning Shift
Subject: Physics
Chapter: Experimental Physics

JEE Main 2020 · 3 September · Morning Shift · Physics · Experimental Physics

Using screw gauge of pitch 0 . 1cm and 50 divisions on its circular...

Using screw gauge of pitch

0 . 1cm

and

50

divisions on its circular scale, the thickness of an object is measured. It should correctly be recorded as,

Options

A $2 . 121cm$
B $2 . 124cm$
C $2 . 125cm$
D $2 . 123cm$

Correct answer

B. $2 . 124cm$

Step-by-step solution

Thickness $= M . S .$ Reading $+$ Circular Scale Reading $( L . C . )$

Here least count is $0 . 002cmperdivision .$

From all the four options, the second answer is divisible by this least count. Hence option $2$ is correct.

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