JEE Main20203 Sep 2020Morning ShiftPhysicsExperimental PhysicsActual
Using screw gauge of pitch 0 . 1 cm and 50 divisions on its circular scale, the thickness of an object is measured. It should correctly be recorded as,
Options
- A2 . 121 cm
- B2 . 124 cm
- C2 . 125 cm
- D2 . 123 cm
Correct answer
B. 2 . 124 cm
Step-by-step solution
Thickness =   M . S . Reading + Circular Scale Reading ( L . C . ) Here least count is 0 . 002   cm   per   division . From all the four options, the second answer is divisible by this least count. Hence option 2 is correct.