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JEE Main 20199 JanuaryEvening Shift
Exam
JEE Main
Year
2019
Date
9 January
Shift
Evening Shift
Subject
Physics
Chapter
Experimental Physics

JEE Main 2019 · 9 January · Evening Shift · Physics · Experimental Physics

The pitch and the number of divisions, on the circular scale, for a...

The pitch and the number of divisions, on the circular scale, for a given screw gauge are 0.5mm0 . 5mm and 100100 respectively. When the screw gauge is fully tightened without any object, the zero of its circular scale lies 33 divisions below the mean line.

The readings of the main scale and the circular scale, for a thin sheet, are 5.5mm5 .5 mm and 4848 respectively, the thickness of this sheet is:

Options

  1. A5.755mm5.755mm
  2. B5.740mm5.740mm
  3. C5.725mm5.725mm
  4. D5.950mm5.950mm

Correct answer

C. 5.725mm5.725mm

Step-by-step solution

least count =0.5mm100=0.005mm= \dfrac{0.5mm}{100} = 0.005mm

Reading =5.5mm+(48−3)×0.005mm= 5.5mm + \left(48 - 3\right) \times 0.005mm

=5.725mm.= 5.725mm .

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