JEE Main20199 Jan 2019Evening ShiftPhysicsExperimental PhysicsActual
The pitch and the number of divisions, on the circular scale, for a given screw gauge are 0 . 5 mm and 100 respectively. When the screw gauge is fully tightened without any object, the zero of its circular scale lies 3 divisions below the mean line. The readings of the main scale and the circular scale, for a thin sheet, are 5 .5 mm and 48 respectively, the thickness of this sheet is:
Options
- A5.755 m m
- B5.740 m m
- C5.725 m m
- D5.950 m m
Correct answer
C. 5.725 m m
Step-by-step solution
least count = 0.5   m m 100 = 0.005   m m Reading = 5.5   m m + 48 - 3 × 0.005   m m = 5.725   m m .