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JEE Main 201815 April
Exam
JEE Main
Year
2018
Date
15 April
Subject
Physics
Chapter
Experimental Physics

JEE Main 2018 · 15 April · Physics · Experimental Physics

In a screw gauge, 5 complete rotations of the screw cause it to...

In a screw gauge, 55 complete rotations of the screw cause it to move a linear distance of 0.25cm0 . 25cm. There are100100 circular scale divisions. The thickness of a wire measured by this screw gauge gives a reading of 44 main scale divisions and 3030 circular scale divisions. Assuming negligible error, the thickness of the wire is

Options

  1. A0.4300cm0 . 4300cm
  2. B0.3150cm0 . 3150cm
  3. C0.0430cm0 . 0430cm
  4. D0.2150cm0 . 2150cm

Correct answer

D. 0.2150cm0 . 2150cm

Step-by-step solution

The Least count=0.255×100cm=5×10−4cm= \dfrac{0.25}{5 \times 100}cm = 5 \times {10}^{- 4}cm.

Reading =4×0.05cm+30×5×10−4cm= 4 \times 0.05cm + 30 \times 5 \times {10}^{- 4}cm
=(0.2+0.0150)cm=0.2150cm= \left(0.2 + 0.0150\right)cm = 0.2150cm

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