JEE Main2015PhysicsExperimental PhysicsActual
Diameter of a steel ball is measured using a Vernier calipers which has divisions of 0.1 cm on its main scale (MS) and 10 divisions of its Vernier scale (VS) match 9 divisions on the main scale. Three such measurements for a ball are given as: S.No. MS (cm) VS divisions 1. 0.5 8 2. 0.5 4 3. 0.5 6 If the zero error is - 0.03 cm, then mean corrected diameter is:
Options
- A0 . 53   cm
- B0 . 56   cm
- C0 . 59   cm
- D0 . 52   cm
Correct answer
C. 0 . 59   cm
Step-by-step solution
L.C. of Vernier calipers =   1   m a i n   s c a l e   d ivision T o t a l   d i v i s o n s   v e r n i e r   s c a l e     = 0.1 10 = 0.01   cm Reading of Vernier calipers = M . S . R .   + L . C × v s   d i v i s i o n s . d 1 = 0.5 + 0.01 × 8 d 2 = 0.5 + 0.01 × 4 d 3 = 0.5 + 0.01 × 6 ∴       Measured diameter are respectively 0 .58   cm         0 .54   cm ,     &