JEE Main202324 Jan 2023Morning ShiftPhysicsMechanical Properties of SolidsActual
A 100 m long wire having cross-sectional area 6 . 25 × 10 - 4 m 2 and Young's modulus is 10 10 N m - 2 is subjected to a load of 250 N , then the elongation in the wire will be :
Options
- A6 . 25 × 10 - 3   m
- B4 × 10 - 4   m
- C6 . 25 × 10 - 6   m
- D4 × 10 - 3   m
Correct answer
D. 4 × 10 - 3   m
Step-by-step solution
As we know, elongation in wire is given by, ∆ l = F l AY ⇒ ∆ l = 250 × 100 6 . 25 × 10 - 4 × 10 10 ⇒ ∆ l = 4 × 10 - 3   m