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JEE Main20248 Apr 2024Evening ShiftPhysicsOscillationsActual

An object of mass 0.2 ~kg executes simple harmonic motion along x axis with frequency of ( 25 ) Hz . At the position x=0.04 ~m the object has kinetic energy 0.5 ~J and potential energy 0.4 ~J . The amplitude of oscillation is _____ cm .

Correct answer

0

Step-by-step solution

aligned & Total energy = K.E. + P.E. & at x=0.04 ~m , T.E. =0.5+0.4=0.9 ~J & aligned T.E & =1 ~m ^2 ~A ^2=0.9 & = 1 2 0.2 (2 25 )^2 A ^2=0.9 A & =0.06 ~m ~A & =6 ~cm aligned aligned

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