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JEE Main 20246 AprilMorning Shift

Exam: JEE Main
Year: 2024
Date: 6 April
Shift: Morning Shift
Subject: Physics
Chapter: Oscillations

JEE Main 2024 · 6 April · Morning Shift · Physics · Oscillations

A particle is doing simple harmonic motion of amplitude 0.06 ~m and...

A particle is doing simple harmonic motion of amplitude

0.06 \mathrm{~m}

and time period

3.14 \mathrm{~s}

. The maximum velocity of the particle is _______

\mathrm{cm} / \mathrm{s}

.

Correct answer

0

Step-by-step solution

We know

\begin{aligned} \mathrm{V}_{\max } & =\omega \mathrm{A} \quad \text{ at mean position } \\ & =\frac{2 \pi}{\mathrm{T}} \mathrm{A}=\frac{2 \pi}{\pi} \times 0.06=0.12 \mathrm{ m} / \mathrm{sec} \\ \mathrm{V}_{\max } & =12 \mathrm{ cm} / \mathrm{sec} \end{aligned}

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