A simple harmonic oscillator has an amplitude A and time period 6 π second. Assuming the oscillation starts from its mean position, the time required by it to travel from x = A to x = 3 2 A will be π x s , where x = _ _ _ _ _ _ _ .

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Correct answer: 2

From phasor diagram particle has to move from P to Q in a circle of radius equal to amplitude of SHM . cos ϕ = 3 A 2 A = 3 2 ⇒ ϕ = π 6 Now, π 6 = ω t ⇒ π 6 = 2 π T t ⇒ π 6 = 2 π 6 π t ⇒ t = π 2 So, x = 2

A simple harmonic oscillator has an amplitude A and time period 6 π second. Assuming the oscillation starts from its mean position, the time required by it to travel from x = A to x = 3 2 A will be π x s , where x = _ _ _ _ _ _ _ .

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