JEE Main202430 Jan 2024Evening ShiftPhysicsOscillationsActual
A simple pendulum is placed at a place where its distance from the earth's surface is equal to the radius of the earth. If the length of the string is 4 m , then the time period of small oscillations will be _________ s . [ take g = π 2 m s - 2 ]
Correct answer
0
Step-by-step solution
Acceleration due to gravity at surface of earth, g = G M R 2 . Now, at distance R from the surface of the earth, g ' = G M R + R 2 = g 4 Therefore, T = 2 π l g 4 ⇒ T = 2 π 4 × 4 g ⇒ T = 2 π 4 π = 8 s