A rectangular block of mass 5 kg attached to a horizontal spiral spring executes simple harmonic motion of amplitude 1 m and time period 3 . 14 s . The maximum force exerted by spring on block is ___ N .

Step-by-step solution

By Newton's second law, F = m a m a x . The maximum acceleration for a SHM is given by a m a x = ω 2 A       . . . ( i ) The time period is given by T = 2 π ω = 3 . 14   s ⇒ ω = 2 π T = 2 π 3 . 14 = 2   rad   s - 1 Thus, the maximum acceleration from equation (i) a m a x = 4 × 1 = 4   m   s - 2 The maximum force is F = 5   kg × 4   m   s - 2 = 20   N