A particle executes S.H.M. of amplitude A along x -axis. At t = 0 , the position of the particle is x = A 2 and it moves along positive x -axis. The displacement of particle in time t is x = A sin ω t + δ , then the value δ will be

Step-by-step solution

Given, the instantaneous equation of motion of the particle is x = A   sin ω t + δ       . . . 1 As the particle is moving along positive x -axis, v = d x d t > 0 . Substitute 0 for t and A 2 for x into equation (1) and solve to calculate the required phase difference. A 2 = A sin ω × 0 + δ ⇒ sin δ = 1 2 = sin π 6 ⇒ δ = π 6