A body is performing simple harmonic with an amplitude of 10 cm . The velocity of the body was tripled by air Jet when it is at 5 cm from its mean position. The new amplitude of vibration is x cm . The value of x is _____ .

Step-by-step solution

In SHM, velocity of the particle at any displacement, x is given by, v = A 2 - x 2 . Therefore, ⇒ v 3 v = A 1 2 - 25 A 2 2 - 25 ⇒ A 2 2 - 25 = 3 × 75 ⇒ A 2 2 = 700 ⇒ A 2 = 700   cm