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JEE Main202227 Jun 2022Evening ShiftPhysicsOscillationsActual

The equation of a particle executing simple harmonic motion is given by x = sin π t + 1 3 m . At t = 1 s , the speed of particle will be (Given: π = 3 . 14 )

Options

  1. A157   cm   s - 1
  2. B0   cm   s - 1
  3. C272   cm   s - 1
  4. D314   cm   s - 1

Correct answer

A. 157   cm   s - 1

Step-by-step solution

Given, x = sin π t + π 3 Velocity v = d x d t = π cos π t + π 3 Now, at t = 1   s , v = π cos π + π 3 v = - π 2 = - 3 . 14 2 = - 1 . 57   m   s - 1 ⇒ v = 157   cm   s - 1

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