JEE Main202227 Jun 2022Evening ShiftPhysicsOscillationsActual
The equation of a particle executing simple harmonic motion is given by x = sin π t + 1 3 m . At t = 1 s , the speed of particle will be (Given: π = 3 . 14 )
Options
- A157   cm   s - 1
- B0   cm   s - 1
- C272   cm   s - 1
- D314   cm   s - 1
Correct answer
A. 157   cm   s - 1
Step-by-step solution
Given, x = sin π t + π 3 Velocity v = d x d t = π cos π t + π 3 Now, at t = 1   s , v = π cos π + π 3 v = - π 2 = - 3 . 14 2 = - 1 . 57   m   s - 1 ⇒ v = 157   cm   s - 1