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JEE Main202227 Jun 2022Evening ShiftPhysicsOscillationsActual

A particle executes simple harmonic motion. Its amplitude is 8 cm and time period is 6 s . The time it will take to travel from its position of maximum displacement to the point corresponding to half of its amplitude, is _____ s

Correct answer

0

Step-by-step solution

Given here, A = 8   cm and T = 6   s The displacement equation in SHM, when amplitude is halved is A cos 2 π t T = A 2 ⇒ 2 π t T = π 3 Time taken by the particle is t = T 6 = 6 6 = 1 sec .

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