JEE Main202127 Jul 2021Morning ShiftPhysicsOscillationsActual
A particle starts executing simple harmonic motion ( SHM ) of amplitude a and total energy E . At any instant, its kinetic energy is 3 E 4 , then its displacement y is given by:
Options
- Ay = a
- By = a 2
- Cy = a 3 2
- Dy = a 2
Correct answer
D. y = a 2
Step-by-step solution
E = 1 2 K a 2 3 E 4 = 1 2   K a 2 - y 2 v 3 4 × 1 2 K a 2 = 1 2   K a 2 - y 2 y 2 = a 2 - 3 a 2 4 y = a 2