JEE Main202621 January 2026Evening ShiftPhysicsRotational MotionActual
Two cars A and B each of mass 10³ ~kg are moving on parallel tracks separated by a distance of 10 m, in same direction with speeds 72 ~km / h and 36 ~km / h . The magnitude of angular momentum of car A with respect to car B is _ _ _ _ J.s.
Options
- A2 10⁵
- B10⁵
- C3.6 10⁵
- D3 10⁵
Correct answer
B. 10⁵
Step-by-step solution
Mass of each car m = 10^3 kg. Speed of car A , v_A = 72 km/h = 72 5 18 = 20 m/s. Speed of car B , v_B = 36 km/h = 36 5 18 = 10 m/s. Relative velocity of car A with respect to car B is v_ AB = v_A - v_B = 20 - 10 = 10 m/s. The cars are moving on parallel tracks separated by a perpendicular distance d = 10 m. The magnitude of angular momentum of car A with respect to car B is given by L = m v_ AB d . Substituting the values: L = 10^3 10 10 = 10^5 J.s. Thus, the correct option is (2).