JEE Main20253 Apr 2025Morning ShiftPhysicsRotational MotionActual
A force of 49 N acts tangentially at the highest point of a sphere (solid) of mass 20 kg , kept on a rough horizontal plane. If the sphere rolls without slipping, then the acceleration of the center of the sphere is
Options
- A3.5 ~m / s ^2
- B0.35 ~m / s ^2
- C2.5 ~m / s ^2
- D0.25 ~m / s ^2
Correct answer
A. 3.5 ~m / s ^2
Step-by-step solution
Torque about bottom point aligned & F 2 r = I & 49 2 r = 7 5 mr ^2 & 14=4 r aligned As sphere rolls without slipping aligned & a = r & a = 14 4 = 7 2 =3.5 ~m / s ^2 aligned