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JEE Main 20252 AprilMorning Shift
Exam
JEE Main
Year
2025
Date
2 April
Shift
Morning Shift
Subject
Physics
Chapter
Rotational Motion

JEE Main 2025 · 2 April · Morning Shift · Physics · Rotational Motion

A square Lamina OABC of length 10 cm is pivoted at 'O'. Forces act...

A square Lamina OABC of length 10 cm is pivoted at 'O'. Forces act at Lamina as shown in figure. If Lamina remains stationary, then the magnitude of F is :
A square Lamina OABC of length 10 cm is pivoted at 'O'. Forces act at Lamina as shown in figure. If Lamina remains

Options

  1. A20 N
  2. B0 (zero)
  3. C10 N
  4. D102 N10 \sqrt{2} \mathrm{~N}

Correct answer

C. 10 N

Step-by-step solution

Since the lamina is equilibrium.
∴Fnet=0&τnet=0\therefore \mathrm{F}_{\mathrm{net}}=0 \& \tau_{\mathrm{net}}=0
A square Lamina OABC of length 10 cm is pivoted at 'O'. Forces act at Lamina as shown in figure. If Lamina remains
To=10ℓ−Fℓ⇒F=10 N\mathrm{T}_{\mathrm{o}}=10 \ell-\mathrm{F} \ell \Rightarrow \mathrm{F}=10 \mathrm{~N}
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