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JEE Main 202529 JanuaryEvening Shift
Exam
JEE Main
Year
2025
Date
29 January
Shift
Evening Shift
Subject
Physics
Chapter
Rotational Motion

JEE Main 2025 · 29 January · Evening Shift · Physics · Rotational Motion

Three equal masses m are kept at vertices (A, B, C) of an...

Three equal masses m are kept at vertices (A, B, C) of an equilateral triangle of side a in free space. At t=0 , they
Three equal masses mm are kept at vertices (A, B, C) of an equilateral triangle of side a in free space. At t=0t=0, they are given an initial velocity V⃗A=V0AC→,V⃗B=V0BA→\vec{V}_A=V_0 \overrightarrow{A C}, \vec{V}_B=V_0 \overrightarrow{B A} and V⃗C=V0CB→\vec{V}_C=V_0 \overrightarrow{C B}. Here, AC→,CB→\overrightarrow{A C}, \overrightarrow{C B} and BA→\overrightarrow{B A} are unit vectors along the edges of the triangle. If the three masses interact gravitationally, then the magnitude of the net angular momentum of the system at the point of collision is :

Options

  1. A3amV03 \mathrm{a} \mathrm{m} \mathrm{V}_0
  2. B32\frac{3}{2} a mV0\mathrm{m} \mathrm{V}_0
  3. C32\frac{\sqrt{3}}{2} a mV0\mathrm{m} \mathrm{V}_0
  4. D12\frac{1}{2} a mV0\mathrm{mV}_0

Correct answer

C. 32\frac{\sqrt{3}}{2} a mV0\mathrm{m} \mathrm{V}_0

Step-by-step solution

d=a23d=\frac{a}{2 \sqrt{3}} Angular momentum of one mass about point OOL=mvd=mv0⋅a23\begin{aligned} L & =m v d \\ & =m v_0 \cdot \frac{a}{2 \sqrt{3}} \end{aligned}Net angular momentum about point $O\begin{aligned} L_{\text{net }} & =32 \\ & =\frac{\sqrt{3} m v_0 a}{2} \end{aligned}$$$
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