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JEE Main 202524 JanuaryEvening Shift
Exam
JEE Main
Year
2025
Date
24 January
Shift
Evening Shift
Subject
Physics
Chapter
Rotational Motion

JEE Main 2025 · 24 January · Evening Shift · Physics · Rotational Motion

A solid sphere and a hollow sphere of the same mass and of same...

A solid sphere and a hollow sphere of the same mass and of same radius are rolled on an inclined plane. Let the time taken to reach the bottom by the solid sphere and the hollow sphere be t1t_1 and t2t_2, respectively, then

Options

  1. At1>t2t_1\gt t_2
  2. Bt1=t2t_1=t_2
  3. Ct1<t2t_1 \lt t_2
  4. Dt1=2t2t_1=2 t_2

Correct answer

C. t1<t2t_1 \lt t_2

Step-by-step solution

t=2ℓacmacm=gsin⁡θ1+IcmMR2a1=acm1=5gsin⁡θ7….. Solid a2=acm2=3gsin⁡θ5….. Hollow a1>a2t1<t2\begin{aligned} & \mathrm{t}=\sqrt{\frac{2 \ell}{\mathrm{a}_{\mathrm{cm}}}} \\ & \mathrm{a}_{\mathrm{cm}}=\frac{\mathrm{g} \sin \theta}{1+\frac{\mathrm{I}_{\mathrm{cm}}}{\mathrm{MR}^2}} \\ & \mathrm{a}_1=\mathrm{a}_{\mathrm{cm}_1}=\frac{5 \mathrm{ g} \sin \theta}{7} \ldots . . \text{ Solid } \\ & \mathrm{a}_2=\mathrm{a}_{\mathrm{cm}_2}=\frac{3 \mathrm{ g} \sin \theta}{5} \ldots . . \text{ Hollow } \\ & \mathrm{a}_1>\mathrm{a}_2 \\ & \mathrm{t}_1 < \mathrm{t}_2\end{aligned}
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