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JEE Main 20244 AprilMorning Shift
Exam
JEE Main
Year
2024
Date
4 April
Shift
Morning Shift
Subject
Physics
Chapter
Rotational Motion

JEE Main 2024 · 4 April · Morning Shift · Physics · Rotational Motion

A solid sphere and a hollow cylinder roll up without slipping on...

A solid sphere and a hollow cylinder roll up without slipping on same inclined plane with same initial speed vv. The sphere and the cylinder reaches upto maximum heights h1h_1 and h2h_2, respectively, above the initial level. The ratio h1:h2h_1: h_2 is n10\frac{n}{10}. The value of nn is______.

Correct answer

0

Step-by-step solution

Gain in P.E. = Loss in K.E. mgh=12mv2(1+K2R2)\mathrm{mgh}=\frac{1}{2} \mathrm{mv}^2\left(1+\frac{\mathrm{K}^2}{\mathrm{R}^2}\right)\mathrm{h} \propto 1+\frac{\mathrm{K}^2}{\mathrm{R}^2} \frac{\mathrm{h}_1}{\mathrm{~h}_2}=\frac{1+\frac{2}{5}}{1+1}=\frac{7}{5 \times 2}=\frac{7}{10} \mathrm{n}=7
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