A cylinder is rolling down on an inclined plane of inclination 60 ° . Its acceleration during rolling down will be x 3 m s - 2 , where x = _______(use g = 10 m s - 2 ).

Step-by-step solution

For rolling motion, the acceleration of the cylinder along the inclined plane can be expressed as a = g s i n θ 1 + I c m M R 2 . . . 1 The moment of inertia of the cylinder can be written as I c m = 1 2 M R 2 . . . 2 From equations (1) and (2), it follows that a = g s i n θ 1 + 1 2 = 2 × 10 × 3 2 3 = 10 3 m s - 2 Therefore, x = 10 .