Moment of inertia of a disc of mass M and radius ' R ' about any of its diameter is M R 2 4 . The moment of inertia of this disc about an axis normal to the disc and passing through a point on its edge will be, x 2 M R 2 . The value of x is ______.

Step-by-step solution

Given here, Moment of inertia of a disc of mass M and radius ' R ' about any of its diameter is M R 2 4 . Moment of inertia of disc about centre is I c m = M R 2 4 + M R 2 4 = M R 2 2 Using parallel axis theorem, we can write I = I c m + M d 2 = M R 2 2 + M R 2 = 3 2 M R 2 Hence, the value of x = 3 .