The radius of gyration of a cylindrical rod about an axis of rotation perpendicular to its length and passing through the center will be _____ m . Given, the length of the rod is 10 3 m .

Step-by-step solution

Moment of inertia of the rod about an axis perpendicular to its length and passing through the centre is I = m l 2 12 . Using the relation, I = m k 2 , we have ⇒ k 2 = l 2 12 ⇒ k = l 12 = l 2 3 = 10 3 2 3 = 5   m