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JEE Main 202131 AugustEvening Shift
Exam
JEE Main
Year
2021
Date
31 August
Shift
Evening Shift
Subject
Physics
Chapter
Rotational Motion

JEE Main 2021 · 31 August · Evening Shift · Physics · Rotational Motion

A system consists of two identical spheres each of mass 1 . 5kg and...

A system consists of two identical spheres each of mass 1.5kg1 . 5kg and radius 50cm50cm at the ends of a light rod. The distance between the centres of the two spheres is 5m.5m . What will be the moment of inertia of the system about an axis perpendicular to the rod passing through its midpoint?A system consists of two identical spheres each of mass 1 . 5kg and radius 50cm at the ends of a light rod. The

Options

  1. A1.905×105kgm21 . 905 \times {10}^{5}kg{m}^{2}
  2. B18.75kgm218 . 75kg{m}^{2}
  3. C19.05kgm219 . 05kg{m}^{2}
  4. D1.875×105kgm21 . 875 \times {10}^{5}kg{m}^{2}

Correct answer

C. 19.05kgm219 . 05kg{m}^{2}

Step-by-step solution

A system consists of two identical spheres each of mass 1 . 5kg and radius 50cm at the ends of a light rod. The
\leftI=(25MR2+Mx2)×2=[25×1.5×(0.5)2+1.5×(2.5)2)]×2=[0.15+9.375]×2=19.05kgm2\leftI = \left(\dfrac{2}{5}M{R}^{2} + M{x}^{2}\right) \times 2 = \left[\dfrac{2}{5} \times 1 . 5 \times {\left(0 . 5\right)}^{2} + 1 . 5 \times {\left(2 . 5\right)}^{2}\right)] \times 2 = [ 0 . 15 + 9 . 375 ] \times 2 = 19 . 05{kgm}^{2}
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