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JEE Main 202125 JulyEvening Shift
Exam
JEE Main
Year
2021
Date
25 July
Shift
Evening Shift
Subject
Physics
Chapter
Rotational Motion

JEE Main 2021 · 25 July · Evening Shift · Physics · Rotational Motion

A solid disc of radius 20cm and mass 10kg is rotating with an...

A solid disc of radius 20cm20cm and mass 10kg10kg is rotating with an angular velocity of 600rpm600rpm, about an axis normal to its circular plane and passing through its centre of mass. The retarding torque required to bring the disc at rest in 10s10s is _________π×10−1Nm\pi \times {10}^{- 1}Nm

Correct answer

0

Step-by-step solution

τ=\DeltaL\Deltat=I(ωf−ωi)\Deltatτ = \dfrac{\DeltaL}{\Deltat} = \dfrac{I\left({\omega}_{f} - {\omega}_{i}\right)}{\Deltat}

τ=mR22×[0−ω]\Deltatτ = \dfrac{\dfrac{m{R}^{2}}{2} \times [ 0 - \omega ]}{\Deltat}

=10×(20×10−2)22×600×π30×10= \dfrac{10 \times {\left(20 \times {10}^{- 2}\right)}^{2}}{2} \times \dfrac{600 \times \pi}{30 \times 10}

=0.4π=4π×10−1= 0 . 4\pi = 4\pi \times {10}^{- 1}

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