- Exam
- JEE Main
- Year
- 2021
- Date
- 25 July
- Shift
- Morning Shift
- Subject
- Physics
- Chapter
- Rotational Motion
JEE Main 2021 · 25 July · Morning Shift · Physics · Rotational Motion
A particle of mass m is moving in time t on a trajectory given by,...
A particle of mass is moving in time on a trajectory given by,
\overset{\to}{r} = 10\alpha{t}^{2}\overset{^}{i} + 5\beta\left(t - 5\right)\overset{^}{j}
where and are dimensional constants.
The angular momentum of the particle becomes the same as it was for at time _____ seconds.
Correct answer
0
Step-by-step solution
\overset{\to}{r} = 10\alpha{t}^{2}\overset{^}{i} + 5\beta\left(t - 5\right)\overset{^}{j}
\overset{\to}{v} = 20\alpha + \overset{^}{i} + 5\beta\overset{^}{j}
= m\left[10\alpha{t}^{2}\overset{^}{i} + 5\beta\left(t - 5\right)\overset{^}{j}\right] \times \left[20\alpha\overset{^}{i} + 5\beta\overset{^}{j}\right]
\overset{\to}{L} = m\left[50\alpha\beta{t}^{2}\overset{^}{k} - 100\alpha\beta\left({t}^{2} - 5t\right)\overset{^}{k}\right]
At