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JEE Main 202122 JulyMorning Shift
Exam
JEE Main
Year
2021
Date
22 July
Shift
Morning Shift
Subject
Physics
Chapter
Rotational Motion

JEE Main 2021 · 22 July · Morning Shift · Physics · Rotational Motion

The centre of a wheel rolling on a plane surface moves with a speed...

The centre of a wheel rolling on a plane surface moves with a speed v0.{v}_{0} . A particle on the rim of the wheel at the same level as the centre will be moving at a speed xv0.\sqrt{x}{v}_{0} . Then the value of xx is .The centre of a wheel rolling on a plane surface moves with a speed v _ 0 . A particle on the rim of the wheel at the

Correct answer

0

Step-by-step solution

The centre of a wheel rolling on a plane surface moves with a speed v _ 0 . A particle on the rim of the wheel at the

For no slipping, v0=\omegaR{v}_{0} = \omegaR
Now, vA=vB=v02+(\omegaR)2{v}_{A} = {v}_{B} = \sqrt{{v}_{0}^{2} + ( \omegaR{)}^{2}}
=2v0= \sqrt{2}{v}_{0}

⇒x=2⇒ x = 2

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