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JEE Main202122 Jul 2021Morning ShiftPhysicsRotational MotionActual

The centre of a wheel rolling on a plane surface moves with a speed v 0 . A particle on the rim of the wheel at the same level as the centre will be moving at a speed x v 0 . Then the value of x is .

Correct answer

0

Step-by-step solution

For no slipping, v 0 = ω R Now, v A = v B = v 0 2 + ( ω R ) 2 = 2 v 0 ⇒ x = 2

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