A solid cylinder of mass m is wrapped with an inextensible light string and, is placed on a rough inclined plane as shown in the figure. The frictional force acting between the cylinder and the inclined plane is: [The

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Correct answer: C. (mg)/(5)

A solid cylinder of mass m is wrapped with an inextensible light string and, is placed on a rough inclined plane as

Let's take solid cylinder is in equilibrium

$T + f = mgsin60$

$TR - fR = 0$

Solving we get

$T = {f}_{req} = \dfrac{mgsin\theta}{2}$

But limiting friction $<$ required friction

$\mu mgcos60 ° < \dfrac{mg \sin 60 °}{2}$

$∴$ Hence cylinder will not remain in equilibrium

Hence $f =$ kinetic

$= {\mu}_{k}N$

$= {\mu}_{k}mgcos60 °$

$= \dfrac{mg}{5}$

A solid cylinder of mass m is wrapped with an inextensible light...

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