JEE Main202118 Mar 2021Evening ShiftPhysicsRotational MotionActual
A solid cylinder of mass m is wrapped with an inextensible light string and, is placed on a rough inclined plane as shown in the figure. The frictional force acting between the cylinder and the inclined plane is: [The coefficient of static friction, μ s , is 0 . 4 ]
Options
- A7 2 m g
- B5 m g
- Cm g 5
- D0
Correct answer
C. m g 5
Step-by-step solution
Let's take solid cylinder is in equilibrium T + f = m g sin 60 T R - f R = 0 Solving we get T = f r e q = m g sin θ 2 But limiting friction < required friction μ m g cos 60 ° < mg sin 60 ° 2 ∴ Hence cylinder will not remain in equilibrium Hence f = kinetic = μ k N = μ k m g cos 60 ° = m g 5