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JEE Main 202117 MarchMorning Shift
Exam
JEE Main
Year
2021
Date
17 March
Shift
Morning Shift
Subject
Physics
Chapter
Rotational Motion

JEE Main 2021 · 17 March · Morning Shift · Physics · Rotational Motion

A triangular plate is shown. A force → F = 4 ^ i - 3 ^ j is applied...

A triangular plate is shown. A force \overset{\to}{F} = 4\overset{^}{i} - 3\overset{^}{j} is applied at point P.P . The torque at point PP with respect to point OO and QQ are:

A triangular plate is shown. A force → F = 4 ^ i - 3 ^ j is applied at point P . The torque at point P with respect to

Options

  1. A−15−203,15−203- 15 - 20\sqrt{3}, 15 - 20\sqrt{3}
  2. B15+203,15−20315 + 20\sqrt{3}, 15 - 20\sqrt{3}
  3. C15−203,15+20315 - 20\sqrt{3}, 15 + 20\sqrt{3}
  4. D−15+203,15+203- 15 + 20\sqrt{3}, 15 + 20\sqrt{3}

Correct answer

A. −15−203,15−203- 15 - 20\sqrt{3}, 15 - 20\sqrt{3}

Step-by-step solution

\overset{\to}{F} = 4\overset{^}{i} - 3\overset{^}{j}

\overset{\to}{r}1 = 5\overset{^}{i} + 5\sqrt{3}\overset{^}{j} and \overset{\to}{r}2 = - 5\overset{^}{i} + 5\sqrt{3}\overset{^}{j}

Torque about ′O′' O '

\overset{\to}{τ}O = \overset{\to}{r}1 \times \overset{\to}{F} = \left(- 15 - 20\sqrt{3}\right)\overset{^}{k}

Torque about ′Q′' Q '

\overset{\to}{τ}Q = \overset{\to}{r}2 \times \overset{\to}{F} = \left(15 - 20\sqrt{3}\right)\overset{^}{k}

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