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JEE Main202116 Mar 2021Morning ShiftPhysicsRotational MotionActual

Four equal masses, m each are placed at the corners of a square of length l as shown in the figure. The moment of inertia of the system about an axis passing through A and parallel to D B would be :

Options

  1. Am l 2
  2. B2   m l 2
  3. C3   m l 2
  4. D3   m l 2

Correct answer

C. 3   m l 2

Step-by-step solution

Moment of inertia of point mass = mass × Perpendicular   distance   from   axis 2 Moment of Inertia = m 0 2 + m l 2 2 + m l 2 2 + m l 2 2 = 3   m l 2

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