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JEE Main 202116 MarchMorning Shift
Exam
JEE Main
Year
2021
Date
16 March
Shift
Morning Shift
Subject
Physics
Chapter
Rotational Motion

JEE Main 2021 · 16 March · Morning Shift · Physics · Rotational Motion

A ball of mass 10kg moving with a velocity 10 3 ms ^ - 1 along X...

A ball of mass 10kg10kg moving with a velocity 103ms−110\sqrt{3}{ms}^{- 1} along XX-axis, hits another ball of mass 20kg20kg which is at rest. After the collision, the first ball comes to rest and the second one disintegrates into two equal pieces. One of the pieces starts moving along YY-axis at a speed of 10ms−110m{s}^{- 1}. The second piece starts moving at a speed of 20ms−120m{s}^{- 1} at an angle θ\theta (degree) with respect to the XX-axis. The configuration of pieces after the collision is shown in the figure. The value of θ\theta to the nearest integer is _________.

A ball of mass 10kg moving with a velocity 10 3 ms ^ - 1 along X -axis, hits another ball of mass 20kg which is at

Correct answer

0

Step-by-step solution

Before Collision

A ball of mass 10kg moving with a velocity 10 3 ms ^ - 1 along X -axis, hits another ball of mass 20kg which is at

After Collision

A ball of mass 10kg moving with a velocity 10 3 ms ^ - 1 along X -axis, hits another ball of mass 20kg which is at

From conservation of momentum along xx axis;

P→i=P→f\overset{\to}{P}i = \overset{\to}{P}f

10×103=200cosθ10 \times 10\sqrt{3} = 200cos\theta

cosθ=32cos\theta = \dfrac{\sqrt{3}}{2}

θ=30°\theta = 30 °

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