JEE Main202124 Feb 2021Morning ShiftPhysicsRotational MotionActual
Moment of inertia M . I . of four bodies, having same mass and radius, are reported as; I 1 = M . I . of thin circular ring about its diameter, I 2 = M . I . of circular disc about an axis perpendicular to disc and going through the centre, I 3 = M . I . of solid cylinder about its axis and I 4 = M . I . of solid sphere about its diameter. Then:
Options
- AI 1 + I 2 = I 3 + 5 2 I 4 .
- BI 1 + I 3 < I 2 + I 4
- CI 1 = I 2 = I 3 > I 4
- DI 1 = I 2 = I 3 < I 4
Correct answer
C. I 1 = I 2 = I 3 > I 4
Step-by-step solution
Ring I 1 = M R 2 2 about diameter Disc I 2 = M R 2 2 Solid cylinder I 3 = M R 2 2 Solid sphere I 4 = 2 5 M R 2 I 1 = I 2 = I 3 > I 4