JEE Main20206 Sep 2020Morning ShiftPhysicsRotational MotionActual
Shown in the figure is a hollow ice-cream cone (it is open at top). If its mass is M , radius of its top is R and height, H , then its moment of inertia about its axis is
Options
- AMR 2 2
- BM R 2 + H 2 4
- CMH 2 3
- DMR 2 3
Correct answer
A. MR 2 2
Step-by-step solution
It can be assumed as several parts of discs having different radius, so I = ∫ dl = ∫ dm r 2 From diagram r y = tan θ = R H r = R H · y dm = ρ π r 2 dy From equation (i), (ii) and (iii) I = M R 2 2