JEE Main20208 Jan 2020Evening ShiftPhysicsRotational MotionActual
A uniform sphere of mass 500 g rolls without slipping on a plane horizontal surface with its centre moving at a speed of 5.00 cm s - 1 . Its kinetic energy is:
Options
- A8.75 × 10 - 4 J
- B8.75 × 10 - 3 J
- C6.25 × 10 - 4 J
- D1.13 × 10 - 3 J
Correct answer
A. 8.75 × 10 - 4 J
Step-by-step solution
K . E of the sphere = Translational K . E + Rotational K . E = 1 2 m v 2 1 + K 2 R 2   , K = Radius of gyration =   1 2 × 1 2 × 2 100 2 1 + 2 5 =   35 4 × 10 - 4   J = 8.75 × 10 - 4   J