JEE Main2014PhysicsRotational MotionActual
Consider a cylinder of mass M resting on a rough horizontal rug that is pulled out from under it with acceleration 'a' perpendicular to the axis of the cylinder. What is F friction at point P ? It is assumed that the cylinder does not slip.
Options
- AMa
- BMa 2
- CMa 3
- DMg
Correct answer
C. Ma 3
Step-by-step solution
For no slipping at P a 1 + α R = a    → (1) f = Ma 1 = M a - α R    → (2) f. R = I · α = MR 2 2 · α    → (3) Solve the equations (2) and (3) f = Ma 3