JEE Main2014PhysicsRotational MotionActual
A mass m is supported by a massless string wound around a uniform hollow cylinder of mass m and radius R. If the string does not slip on the cylinder, with what acceleration will the mass fall on release?
Options
- A2 g 3
- Bg 2
- C5 g 6
- Dg
Correct answer
B. g 2
Step-by-step solution
mg - T = ma ----- 1 TR = Iα TR = mR 2 α ∴ T = mR α ----2 For no slippping a = Rα ---3 putting (3) in (2) T = ma ---4 Adding 1 and 4 mg = 2ma ∴   a = g 2