JEE Main2013PhysicsRotational MotionActual
A tennis ball (treated as hollow spherical shell) starting from O rolls down a hill. At point A the ball becomes air borne leaving at an angle of 30^ with the horizontal. The ball strikes the ground at B . What is the value of the distance AB ? (Moment of inertia of a spherical shell of mass m and radius R about its diameter = 2 3 m R^2 )
Options
- A1.87 ~m
- B2.08 ~m
- C1.57 ~m
- D1.77 ~m
Correct answer
B. 2.08 ~m
Step-by-step solution
Velocity of the tennis ball on the surface of the earth or ground aligned & v = 2 gh 1+ k ^2 R ^2 ( where k = radius of gyration & of spherical shell .= 2 3 R ) & Horizontal range AB = v ^2 2 g & = . 2 gh 1+ k ^2 / R ^2 )^2 (2 30^ ) g aligned