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JEE Main 20254 AprilEvening Shift
Exam
JEE Main
Year
2025
Date
4 April
Shift
Evening Shift
Subject
Physics
Chapter
Thermal Properties of Matter

JEE Main 2025 · 4 April · Evening Shift · Physics · Thermal Properties of Matter

Consider a rectangular sheet of solid material of length =9 ~cm and...

Consider a rectangular sheet of solid material of length ℓ=9 cm\ell=9 \mathrm{~cm} and width d=4 cm\mathrm{d}=4 \mathrm{~cm}. The coefficient of linear expansion is α=3.1×10−5 K−1\alpha=3.1 \times 10^{-5} \mathrm{~K}^{-1} at room temperature and one atmospheric pressure. The mass of sheet m=0.1 kg\mathrm{m}=0.1 \mathrm{~kg} and the specific heat capacity Cv=900 J kg−1 K−1\mathrm{C}_{\mathrm{v}}=900 \mathrm{~J} \mathrm{~kg}^{-1} \mathrm{~K}^{-1}. If the amount of heat supplied to the material is 8.1×102 J8.1 \times 10^2 \mathrm{~J} then change in area of the rectangular sheet is :-

Options

  1. A2.0×10−6 m22.0 \times 10^{-6} \mathrm{~m}^2
  2. B3.0×10−7 m23.0 \times 10^{-7} \mathrm{~m}^2
  3. C6.0×10−7 m26.0 \times 10^{-7} \mathrm{~m}^2
  4. D4.0×10−7 m24.0 \times 10^{-7} \mathrm{~m}^2

Correct answer

A. 2.0×10−6 m22.0 \times 10^{-6} \mathrm{~m}^2

Step-by-step solution

ΔQ=msΔT8.1×102=0.1×900×ΔTΔA=A02αΔ T=2.0×10−6 m2\begin{aligned} & \Delta \mathrm{Q}=\mathrm{ms} \Delta \mathrm{T} \\ & 8.1 \times 10^2=0.1 \times 900 \times \Delta \mathrm{T} \\ & \Delta \mathrm{A}=\mathrm{A}_0 2 \alpha \Delta \mathrm{~T}=2.0 \times 10^{-6} \mathrm{~m}^2\end{aligned}
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