A copper block of mass 5 . 0kg is heated to a temperature of 500 °...

Given, mass of copper block $m = 5kg$

Change in temperature \left(\Delta \text{t}\right) = 500 ° \text{C}$<br /><br />Specific heat$s = 0 . 39J{( g - ° C )}^{- 1}$<br /><br />Latent heat of fusion of water$L = 335J{g}^{- 1}$<br /><br />Heat energy absorbed by copper block,${\text{Q}_{1} = \text{ms} \Delta \text{t}$<br /><br />Let$m ' kg$of ice be melted.<br /><br />Heat energy required to melt ice,${Q}_{2} = m ' L$<br /><br />But heat energy absorbed by copper block is heat energy utilised by ice in melting,${Q}_{1} = {Q}_{2}$.<br />$\text{ms} \Delta \text{t} = {\text{m}}^{'}\text{L}$<br />or${\text{m}}^{'} = \dfrac{\text{ms} \Delta \text{t}}{\text{L}} = \dfrac{5 \times 0 . 39 \times 500}{335} = 2 . 9kg