Due to cold weather, a 1m water pipe of cross-sectional area 1 cm ^...

The mass of ice, $m = ρAL = {10}^{3} \times {10}^{- 4} \times 1 = {10}^{- 1}kg$,

Energy required to melt the ice, $= mS\DeltaT + mL$,

$⇒ {i}^{2}Rt = mS\DeltaT + mL$
$⇒ ( 1{)}^{2} \times {10}^{3} \times t = \left[\left({10}^{3} \times 1 \times {10}^{- 4}\right) \times 2000 \times 10\right] + \left[\left({10}^{3} \times 1 \times {10}^{- 4}\right) \times 330 \times {10}^{3}\right] ⇒ ( 1{)}^{2} \times {10}^{3} \times t = 3 . 53 \times {10}^{4} ⇒ t = 35 . 3s$